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Get college assignment help at uniessay writers Consider a plant in optimal light conditions (during daylight hours) and answer the following three questions. Q: Is it possible for this plant to consistently do the same amount of photosynthesis and respiration? (Be aware! The sun will set eventually, leaving our plant in the dark!) Why or why not?

Two organisms, each with the genotypes TtGg, mate. What are the

Two organisms, each with the genotypes TtGg, mate. What are the chances of them producing an offspring that has the dominant phenotype for height (T) and the recessive phenotype for color (g)?

which of the following is a metabolic taxicab that shuttles electrons

which of the following is a metabolic taxicab that shuttles electrons

If an albino (recessive) woman is married to a man with

If an albino (recessive) woman is married to a man with normal coloring and they have an albino child, what was the genotype of the man?

What is the approximate efficiency of cellular respiration for a mutant

What is the approximate efficiency of cellular respiration for a mutant organism that produces only 29 moles of ATP for every mole of glucose oxidized, rather than the usual 36-38 moles of ATP?

6. Do you think any changes had occurred in the carrying

6. Do you think any changes had occurred in the carrying capacity of the range from 1900 to 1940? Explain your answer. from the lesson of the kaibab lab

a material is found in an asteroid that mught be a

a material is found in an asteroid that mught be a cell. what criteria must the material meet to be considered a cell?

signs and symptoms of euglenoid protist, prognosis, appropriate treatment modality, etiology

signs and symptoms of euglenoid protist, prognosis, appropriate treatment modality, etiology (causative) agent of the disease or disease with diagnose.

whats a lysosome acrostic poem

whats a lysosome acrostic poem

Some photosynthetic bacteria (e.g., purple sulfur bacteria) have photosystem I but

Some photosynthetic bacteria (e.g., purple sulfur bacteria) have photosystem I but not II, while others (e.g. cyanobacteria) have both PSI and PSII. Which of the following might this observation imply? Photosystem II must have been selected against in some species. Photosystem II may have evolved to be more photoprotective. Cyclic flow must be more primitive than linear flow of electrons. Cyclic flow must be the most necessary of the two processes. Photosystem I must be more ancestral.

how do abiotic factors affect the benthic zone?

Get college assignment help at uniessay writers how do abiotic factors affect the benthic zone?

Recall that the complex oxidation of a mole of glucose releases

Recall that the complex oxidation of a mole of glucose releases 686 kcal of energy. The phosphorylation of ADP to form ATP stores approximately 7.3 kcal per mole o ATP. What is the approximate efficiency of cellular respiration for a “mutant” organism that produces only 29 moles of ATP for every mole of glucose oxidized, rather than the usual 36-38 moles of ATP?

In the ________ model, memory is seen as a simultaneous process,

In the ________ model, memory is seen as a simultaneous process, with the creation and storage of memories taking place across a series of networks “stretched”across the brain.

Which of the following pairs is mismatched? A) Subacute bacterial endocarditis

Which of the following pairs is mismatched? A) Subacute bacterial endocarditis  alpha-hemolytic streptococci B) Acute bacterial endocarditis  Staphylococcus aureus C) Pericarditis  Streptococcus pneumoniae D) Puerperal sepsis  Staphylococcus aureus E) None of the above

Which of the following pairs is mismatched? A) Rickettsia  intracellular

Which of the following pairs is mismatched? A) Rickettsia  intracellular parasite B) Brucella  gram-negative aerobic rods C) Francisella  gram-positive facultatively anaerobic pleomorphic rods D) Bacillus  gram-positive endospore-forming rods E) None of the above

74) Mitochondria are thought to be the descendants of certain alpha-proteobacteria.

74) Mitochondria are thought to be the descendants of certain alpha-proteobacteria. They are, however, no longer able to lead independent lives because most genes originally present on their chromosome have moved to the nuclear genome. Which phenomenon accounts for the movement of these genes?

**LOOK AT ATTACHMENT INSTEAD** 1. Caenorhabditis elegans (the famous model genetic

**LOOK AT ATTACHMENT INSTEAD** 1. Caenorhabditis elegans (the famous model genetic organism) has 6 different chromosomes: 5 autosomes (called I-V) and 1 sex chromosome (called X). That is, n=6 for hermaprhodites (which are basically XX females that make both sperm and eggs). Hermaphrodites can either self-fertilize or they can be fertilized by males (which only have one X chromosome per diploid cell; i.e. males are hemizygous and designated “XO”, where the “O” just represents no chromosome, “nullo”). How many chromatids per nucleus (in a diploid somatic cell) will there be in a hermaphrodite of C. elegans at prophase of mitosis? A. 6 B. 11 C. 12 D. 22 E. 24 2. How many chromatids per diploid nucleus (in a diploid somatic cell) will there be at telophase of mitosis in C. elegans male cells? (Hint: a cell in telophase contains two separate nuclei.) A. 6 B. 11 C. 12 D. 22 E. 24 3. During meiosis I of spermatogenesis in C. elegans males, what arrangement will be found at the metaphase plate? (Reminder: a tetrad is a complex of four chromatids; a dyad is a complex of two chromatids.) A. The autosomes will form tetrads and the X will exist as a dyad. B. All chromosomes will form tetrads. C. The autosomes will form tetrads, and the X and O will pair as a tetrad. D. No tetrads will form in this case because males are hemizygous. E. The autosomes will form dyads and the X will form a tetrad. 4. After meiosis II of spermatogenesis in males of C. elegans, how many chromatids will each gamete have? A. Half the gametes will have 5 and half will have 6. B. All the gametes will have 6 chromatids. C. All the gametes will have 5 chromatids. D. One quarter have 5 chromatids, and the rest will have 6 chromatids. E. Half the gametes will have 11 and half will have 12. 5. During the cell cycle, there are proteins that are involved in degrading cyclins. According to the model in your book (Fig. 12.17), what would happen if such proteins were compromised by mutation such that they could not function well? A. The concentration of free Cdk would increase, resetting the G2 checkpoint. B. Less MPF would be made than normal. C. Phosphorylation of mitosis-inducing molecules would be prevented. D. Cells would not be “checked” at G2, and the cell cycle could not be stopped. E. The activity of the cyclin-dependent kinase enzyme would be reduced. 6. In peas, flower color is influenced by gene p. One allele at this locus, P, is dominant and causes flowers to be purplish. Another allele at this locus, p, is recessive and fails to produce purple pigment. You possess a pea plant producing purple flowers, but are unsure of their genotype (except that you know they cannot be homozygous pp). How could you distinguish between the hypotheses that the plant is heterozygous Pp versus homozygous PP? A. Cross the plant with a known homozygous dominant to see if all the progeny are purple or not. B. Cross the plant with another purple-flower plant to see if you get any white progeny or not. C. Cross the plant with a white-flower plant to see if you get any white progeny or not. D. Cross the plant with a white-flower plant to check for pinkish flowers in the progeny. E. Dissect the flowers to see if the anthers are all the same or not. 7. Wild-type C. elegans worms are skinny and move in an elegant sinusoidal, curvy pattern, like some snakes. Homozygous dpy(-)/dpy(-) mutants are dumpy (short and fat); homozygous unc(-)/unc(-) mutants are uncoordinated. Assume that the dpy gene segregates independently from the unc gene, and that the wild-type alleles dpy( ) and unc( ) are completely dominant to the mutant alleles dpy(-) and unc(-), respectively. What are the expected results in the F2 generation from selfing an F1 hermaphrodite that came from a cross between a homozygous dumpy-only male (dpy(-)/dpy(-) ; unc( )/unc( )) and a homozygous uncoordinated-only hermaphrodite (unc(-)/unc(-) ; dpy( )/dpy( ))? (Hermaphrodites in this cross behave as females. Hermaphrodite F1s, however, are allowed to self.) A. 1/16 of the F2 progeny will be both dumpy and uncoordinated. B. 3/16 of the F2 progeny will be both dumpy and uncoordinated. C. 9/16 of the F2 progeny will be both dumpy and uncoordinated. D. All of the F2 progeny will be both dumpy and uncoordinated. E. None of the F2 progeny will be both dumpy and uncoordinated. 8. For the pedigree above, assume that the allele responsible for the trait of individuals indicated with colored symbols is T and the wildtype allele is . What are the genotypes of the two most recently born individuals? (Hint: do not let the symbols fool you.) A. are T and . B. are TT and T . C. are TT and . D. are TT for one and either or T for the other. E. cannot be determined for either individual with certainty. 9. First, find out from your book or another resource what is the diploid number of chromosomes for humans. Ignoring recombination, for a normal diploid human couple, what would be the total number of different chromosomal combinations that are possible in zygotes made by the union of their gametes? A. 23 B. 223 C. 423 D. 446 E. infinte 10. A woman and her spouse both show the normal phenotype for pigmentation, but both had a parent who was albino. Albinism is an autosomal recessive trait. If their first two children have normal pigmentation, what is the probability that their third child will be albino? (No need for sophisticated Bayesian probability calculations; just use normal probability calculations.) A. 0.00 B. 0.25 C. 0.50 D. 0.75 E. 1.00

15-44 Fibroblast cells from patients W, X, Y, and Z, each

15-44 Fibroblast cells from patients W, X, Y, and Z, each of whom has a different inherited defect, all contain “inclusion bodies,” which are lysosomes filled with undigested material. You wish to identify the cellular basis of these defects. The possibilities are: 1. a defect in one of the lysosomal hydrolases 2. a defect in the phosphotransferase that is required for mannose-6- phosphate tagging of the lysosomal hydrolases 3. a defect in the mannose-6-phosphate receptor, which binds mannose-6- phosphate-tagged lysosomal proteins in the trans Golgi network and delivers them to lysosomes When you incubate some of these mutant fibroblasts in a medium in which normal cells have been grown, you find that the inclusion bodies disappear. Because of these results, you suspect that the constitutive exocytic pathway in normal cells is secreting lysosomal hydrolases that are being taken up by the mutant cells. (It is known that some mannose-6-phosphate receptor molecules are found in the plasma membrane and can take up and deliver lysosomal proteins via the endocytic pathway.) You incubate cells from each patient with medium from normal cells and medium from each of the other mutant cell cultures, and get the results summarized in Table Q15-44. Table Q15-44 Indicate which defect (1, 2, 3) each patient (W, X, Y, Z) is most likely to have.

“In a bacterium that possesses antibiotic resistance and the potential to

“In a bacterium that possesses antibiotic resistance and the potential to persist through very adverse conditions such as freezing, drying, or hight temperatures, DNA should be located within, or be a part of what structures?”

make an acrostic poem for the word polar as in polar

make an acrostic poem for the word polar as in polar molecules.

write a paragraph using these words sun omnivore carnivore herbivore radiant

write a paragraph using these words sun omnivore carnivore herbivore radiant energy chemical energy ATP ADP Cellular respiration glucose autotroph heterotroph plants oxygen photosynthesis mitochondrion

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